if the quotient obtained on dividing (3x³+11x²+34x+106) by (x-3) is (3x²+ax+b) , then find a and b and also the remainder
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Answer:
We divide the polynomial 3x
3
+11x
2
+34x+106 by x−3 as shown in the above image:
From the above division, we conclude that the quotient is 3x
2
+20x+94 and the remainder is 388.
Hence, the quotient is 3x
2
+20x+94 and the remainder is 388.
Step-by-step explanation:
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