Question

If the quotient obtained on dividing (8x⁴-2x² + 6x - 7) by (2x + 1) is (4x³+px²-qx+ 3), then find p, q and also the remainder.

Please answer this question asap!​

Answer 1

Answer:

The division of (8x4 - 2x 6x - 7) and (2x 1) is shown above:

Therefore, from the division, we get that the quotient is (1/2(8x ^3 -4x^2 + 6)) that is (4x^3-2x^2+3)and the remainder is −10.

But it is also given that the quotient is (4x^3 px ^2 - qx + 3),thus on comparing the coefficients of both the quotients (4x^3- 2x^3+ 3) and (4x^3 - px ^2- qx + 3), we get

p = -2 and

q = 0

Hence, p = -2, q = 0 and the remainder is

(-10)....... hope you understood !!!!