If the quotient on dividing x² +10x³+35x²+50x+29 by (x +4) is x³ -ax²+bx+6.then find the value of a,b and also remainder
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Therefore, from the division, we get that the quotient is (x3+6x2+11x+6) and the remainder is 5.
But it is also given that the quotient is (x3−ax2+bx+6), thus on comparing the coefficients of both the quotients (x3+6x2+11x+6) and (x3−ax2+bx+6), we get
−ax2=6x2
⇒−a=6
⇒a=−6
Also,
bx=11x
⇒b=11
Hence, a= -6, b= 11 & the remainder is 5.
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