Question

. If the r.m.s. speed of a nitrogen molecule at a certain temperature is 980 m/s. What is the temperature of the gas. [Relative molar mass of nitrogen = 28 Molar gas constant = 8.3 J mol-'K] ​

Answer 1

Answer:

Given:

V

rms

=832ms

−1

R=8320J/kmolK

Molar mass, M=28

R.M.S velocity, V

rms

=

M

3RT

Calculation: From formula,

832=

28

3×8320×T

T=

3×8320

832×832×28

=776.5K

The R.M.S. speed of nitrogen molecules is 832ms

−1

at temperature 776.5K

Explanation:

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