If the R1=R2=20 ohm resistors are connectedin series with 200V supply find the power across each resistor
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Explanation:
in series current remain constant
power across each RESISTOR is I²R
I = V /R ( equi)
= 200 / 40 = 5 A
power = 5² x 20 = 25 x 20 = 500 = 0.5KW
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