Question

If the radii of a circular and of frustum of cone are 20 cm and 12 cm and its height is 6 CM then find the slant height of frustum of a cone

Answer 1

$radius \: of \: the \: base \: of \: frustum(r1) = 20cm \\ radius \: of \: the \: top \: part \: of \: frustum(r2) = 12cm \\ height \: of \: frustum(h) = 6cm \\ \\ take \: slant \: height \: as \: l \: of \: frustum. \\ l = \sqrt{(r1 - r2) {}^{2} + {h}^{2} } \\ l = \sqrt{(20 - 12) {}^{2} + {6}^{2} } \\ l = \sqrt{ {8}^{2} + {6}^{2} } \\ l = \sqrt{64 + 36} \\ l = \sqrt{100 } \\ l = 10 \\ \\ slant \: height \: of \: frustum \: is \: 10cm$
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Answer 2

Answer:

l=10

Step-by-step explanation:

so here l=√(r1-r2)^2+h^2

l=√(20-12)^2+6^2

l=√8^2+36

• l=√64+36
• l=√100
• l=10