Question

If the radii of circular end of bucket 45 cm height are 28 cm and 7 cm find the capacity of the bucket (Use $(\pi=\frac{22}{7})$)

Answer 1

Answer:

The capacity of bucket is 48510 cm³.

Step-by-step explanation:

SOLUTION :  

Given :  

Height of a conical bucket, (h) = 45 cm

Bigger Radius, R = 28 cm

Smaller Radius, r = 7 cm

Volume (capacity) of conical bucket = π/3 h (R² + r² + Rr)  

= π/3 × 45 [(28)² + (7)² + 28 ×7]

= 15π [ 784 + 49 + 196 ]

= 15π × 1029

= π ×15435

= 22/7 × 15435

= 22 × 2205

= 48510 cm³

Hence, capacity of bucket is 48510 cm³.

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

ANSWER:--

Radius of top of the bucket ( R ) = 15 cm.

Radius of bottom of the bucket ( r ) = 5 cm.

And

Height of the bucket ( H ) = 24 cm.

Therefore,

Slant Height ( L ) = √ ( H )² + ( R - r )²

=> ✓ ( 24)² + ( 15 - 5 )²

=> √576 + (10)²

=> √ 576 + 100

=> √676

=> 26 cm.

• Curved Surface area of bucket = πL ( R + r ) cm².

=> 22/7 × 26 ( 15 + 5 ) cm².

=> ( 22 × 26 ) × 20 / 7 cm².

=> ( 22 × 26 × 20 ) / 7 cm².

=> 1634.28 cm².

hope it helps:)

T!—!ANKS!!!