Question

If the radii of the circular ends bucket 24 cm high 5 cm and 15 cm find surface area of the bucket

Answer 1

first of all, l = √(24)2 + (15 - 5)2 = 26 cm...

Thus, inner curved surface area of the bucket = pi x l x (R + r) + pi x r2 

on putting pi = 3.14 , r = 5, R = 15 and l = 26 we get the I.C.S.A = 1711.30 cm2


 

Answer 2

Answer:

The surface area of a Bucket is 545π cm².

Step-by-step explanation:

SOLUTION :  

Given :  

Height of a conical bucket, (h) = 24 cm

Bigger Radius, R = 15 cm

Smaller Radius, r = 5 cm

Slant height of a bucket , l = √(R - r)² + h²

l = √(15 - 5)² + 24²

l = √10² + 24² = √100 + 576 = √676

Slant height of a frustum,l = 26 cm

surface area of a Bucket = π(R+ r)l + πr²

= π(15 + 5) × 26 + π × 5²

= π(20 × 26 ) + 25π

= π(520 + 25)

= π ( 545)

= 545π cm²

Hence, the Curved surface area of a Bucket is 545π cm².

HOPE THIS ANSWER WILL HELP YOU….