if the radii of the circular ends of a bucket 28cm high, are 28cm and 7cm, find its capacity and total surface area. Answer: 30418cu.cm and 6468sq.cm
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Given -
Height of the bucket = h = 28 cm
Smaller radius of the bucket = r = 7 cm
Larger radius of the bucket = R = 28 cm
The bucket is in the form of a frustum and the volume of frustum has the formula ,
Volume = (π/3)(R²h + r²h + rRh)
=> Volume = (22/21) × (28) × ((28)² + (7)² + 196)
=> Volume = (22/21) × (28) × (1029)
Volume of the bucket = 30184 cm³
Surface of the frustum has the formula , T.S.A = πr² + πR² + πh(R+r)
=> (22/7) × (49+784+980)
=> 5698 cm²
The total surface area of the bucket = 5698 cm²
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