Question

if the radius a sphere is halved how much will its volume reduce of original sphere​

Answer 1

Answer:

the volume is reduced 1/8 times

Step-by-step explanation:

let initial radius be = R

Therefore, final radius, R' = R/2

initial volume V = 4/3πR^3

final volume,

V' = 4/3π(R/2)^3

= 4/3{π(R^3/8)}

=1/8{4/3πR^3}

=1/8 V

therefore V' = 1/8V

the volume is reduced 1/8 times