If the radius and height of a cone are doubled how does the volume change
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Volume of cone (V1) = 1/3 π r^2 h
If radius and height are doubled, new volume,
V2 = 1/3 π (2r)^2 2h
Now V2:V1 = 8:1
So new volume is eight times the previous one
If radius and height are doubled, new volume,
V2 = 1/3 π (2r)^2 2h
Now V2:V1 = 8:1
So new volume is eight times the previous one
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