Question

if the radius and hight of a cone are increased by 10%,then the volume of the cone is increased by

Answer 1

Ans :33.1%

For objectives,

If length is increased by a% ,breadth

by b% then area increases by

[a+b+(ab/100)]%

And if area increases by x% and

height increases by y% then volume

increases by

[x+y+(xy/100)]%

For cone base area is directly

proportional to r^2 thai it's base area

increases by [a+a+(aa/100)]%

Here radius increases by 10%

So,base area increases by [10+10+

(10×10/100)]%=21%

Now height also increase by10%

So,volume increases by [21+10+

(21×10/100)]%=33.1%

Hope it helps.