If the radius of a circle is 2.5 cm the length of the tangent from a point p which is at a distance of 6.5 cm from the centre is
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Question :
- If the radius of a circle is 2.5 cm the length of the tangent from a point p which is at a distance of 6.5 cm from the centre is?
Solution :
- Radius = 2.5 cm
- DISTANCE of tangent = 6 cm
Let BP = x cm
We know that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
In right angled ∆OAP, OA ⟂ AP,
OP² = OA² + AP²
[By Pythagoras theorem]
(2.5 +x)² = (2.5)² + 6² [OP = OA + BP]
6.25 + x² + 5x = 6.25 + 36
x² + 5x - 36 = 0
x² +9x - 4x -36 = 0
[By factorization]
x(x +9) -4(x +9)=0
(x +9) (x -4) = 0
(x +9) = 0 or (x -4) = 0
x = -9 , x = 4
Sides Can't be negative , so x= 4
Hence, the distance of P from the nearest point of the circle B is 4 cm.
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