Question

if the radius of a circle is 4 cm and the length of a chord of the circle is 6 CM then the distance of the chord from the centre is....​

Answer 1

Answer:

2 cm will be the distance

Answer 2

Answer:

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Step-by-step explanation:

Given OC = 4 cm, Chord AB = 6 cm

∵ OC ⊥ AB = bisects AB

=> AC = CB = $\frac{1}{2} (AB)$ = 3 cm

∴ In OCA, OA² + AC²

= 4² + 3² = 16 + 9 = 25 cm

OA² = 25 cm, OA = √25 = 5 cm

Let EF be the chord at a distance of 3 cm from the centre.

Given, Radius (OE) = 5 cm

∴ In △ OGE, EG² = OE² - OG² = (5)² - (3)²

= EG = √(5)²-(3)² = √25-9 = √16 = 4 cm

EF = 2 EG = 2 × 4 cm = 8 cm