If the radius of a circle is decreased by 20%, find the percentage decrease in its area.
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Now, if the radius is decreased by 50% i.e the new radius is r/2 then the new area of the circle will be = π * (r/2)^2 = A/4, where A is the old area. So if we decrease the radius to half of the original area, the area of the circle is decreased to (1/4)th of the original area.
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If the radius of a circular region were decreased by 20 percent, the area of the circular region would decrease by what percent? If we decrease the radius by 20% the new radius is . 8*R so the new area is: pi*(.
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