Question

If the radius of a circle is increased by 20 percent then the area is increased by

Answer 1

Let's say the radius of said circle is r

Then Area, A=πr^2

Now new Radius r'=r + 20/100r = 1.2r

New Area =πr'^2= π (1.2r)^2= 1.44πr^2

Difference in Area D = 1.44πr^2-πr^2 = .44πr^2

So Percentage wise that is

.44πr^2*100/πr^2=44%

Mark me brainliest....!!

Answer 2

44%

Step-by-step explanation:

Let the radius of original circle be r

AS the R IS INCREASED BY 20%

r+20/100of r

r+0.2r=1.2r

AREA= pie r²

22/7*1.2r*1.2r

pie*1.44r²

PERCENTAGE INCREASED BY

pie*1.44r²-pier²/pie r² of 100

0.44*100= 44%