Question

If the radius of a cone is doubled then by how much it's volume is decreased

Answer 1

Answer:

New volume = 4 times earlier volume

Step-by-step explanation:

New radius(r') = 2r

Volume = 1/3 * 22/7 * (r')^2 * h

-> New Volume = 1/3 * 22/7 * 4r^2h (i)

Original volume = 1/3 * 22/7 * r^2 * h(ii)

Dividing (i) by (ii)-> New Volume/ Original Volume=4/1

Thus the new volume will become 4 times the earlier volume

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