If the radius of a current carrying conductor is halved and length
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If radius is halved,
Then
As r is inversely proportion to the magnetic strength
New strength is doubled
As ur question is incomplete I can’t tell about length
But my guess it’s lenght of conductor
That is directly proportional to the magnetic strength
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im just guessing your question...
New Radius=1/2r
therefore new area of cross section [A]=1/4A
New length= 2l
therefore new resistance= 8 times more than the earlier resistance
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