If the radius of a cylinder is decreased by 50 percent and the height increased by 50 percent then find percentage decreased in volume?
Answers
Answer:
62.5%
Step-by-step explanation:
Let r be the radius and h be the height of the cylinder.
∴ Original volume,V = πr²h
(i) Radius is increased by 50%:
New radius, r₁ = r - 50% of r
= r - (50/100) * r
= r - r/2
= r/2.
(ii) Height increased by 50%:
New height, h₁ = h + 50% of h
= h + (50/100) * h
= h + h/2
= 3h/2
∴ New volume,V₁ = πr₁²h₁
= π(r/2)²(3h/2)
= (3/8)πr²h
Decrease in volume = V - V₁
= (1 - 3/8)πr²h
= (5/8)πr²h
%Decrease in volume = [5/8πr²h/πr²h] * 100%
= [5/8] * 100%
= 62.5%.
Therefore, decrease in volume = 62.5%.
Hope it helps!
The radius of a cylinder is decreased by 50 percent and the height increased by 50 percent.
so the
volume before reducing and increasing was
decrease in radius
=> r-50/100 r
=> r-1/2r
=> r-r/2
=> 2r-r/2
=> r/2
Now
increase in height
=> h+50/100h
=>h+1/2h
=> h+h/2
=> 2h+h/2
=> 3h/2
Now
new volume=
volume percent= orginal volume - new volume/original volume*100
=>
=>