Question

if the radius of a cylinder is doubled and the height is halved ,then find the percentage change in volume

Answer 1

volume of Cylinder =πr²h

Now Acc. to question,
Changed Volume of Cylinder=
= π(2r)²(h/2)
= π4r²h/2
=2πr²h

So the change in Volume =
$\frac{2\pi {r}^{2}h }{\pi {r}^{ {2} } h} \times 100\% \\ = 2 \times 100\% \\ = 200\%$
so 200%increase happened...

Hope it Helps..
Regards,
Leukonov.