Math, asked by rabindra6, 1 year ago

If the radius of a cylinder is doubled and the height is halved. what is the ratio between the new curved surface area and the previous curved surface area of the cylinder ?​

Answers

Answered by anirudhsingh87
9
New/previous=2π.2r.h\2\2πrh

new\previous=1:1 Ans

rabindra6: thanks
anirudhsingh87: wlcm
Answered by Anonymous
9

Answer:

Step-by-step explanation:

Let r2and h2 be the radius and height of new cylinder and let r1 and h1 be the height of previous cylinder

Therefore,

2πr2h2=new curve surface area of cylinder

And 2πr1h1=previous surface area of cylinder

Now according to question

R2=2r1

And h2=1/2h1

2πr2h2/2πr1h1

= 2π*2r1* 1/2h1whole divided by 2πr1h1

And by solving it you get 1 as the answer


rabindra6: thanks for help I'll never forget you
Anonymous: it's aite
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