Question

If the radius of a cylinder is doubled keeping its lareral surface area the same,then what is its height?


PLZ SEND WITH PROCESS ​

Answer 1

Answer:

Height is reduced by half

Step-by-step explanation:

Lateral Surface Area of Cylinder LSA

$LSA = 2 \pi r h$

so if radius is doubled and LSA remains

let new height be h1

$LSA = 2 \pi (2r) h_1 = 2 \pi r h$

$2h_1 = h$

$h_{1} = \frac{h}{2}$

Height is reduced by half

Answer 2

Answer:

Let original radius of a cylinder be (r) and original height of the cylinder be (h)

Original lateral surface area of a cylinder =

2πrh

Radius is douled then new radius be (R) =

2r

New height of the cylinder = H

New lateral surface area of the cylinder =

2πRH

Original lateral suface area of a cylinder = New lateral surface area of a cylinder

[ Given : Lateral surface area of both the cylinders are equal ]

2πrh = 2πRH

h = 2H

H = h/2

Hence the height of the new cylinder is Halved from the original cylinder ( h/2 )

Step-by-step explanation:

Hope it helps you....

Follow me and mark my answer as BRAINLIST....

Thank my answers.... Thank u and have a nice day....