Question

if the radius of a cylinder is doubled keeping its lateral surface area the same then what is its height

Answer 1

then height will became 1/2
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Answer 2

Answer:

Let the initial radius and height of the cylinder be r and h .

Then L.S.A.=2πrh

When r is doubled and the L.S.A. remains the same,then the height be h1.

By problem new L.S.A.=2πrh

=2π(2r)(h1)

➪2πrh=4πrh1

Therefore h1=$\frac{2πrh}{4πr}$=$\frac{1}{2}$h

i.e, Height becomes its half.