Math, asked by misharyan50, 4 days ago

If the radius of a cylinder is increased by 20% and its height is decreased by 10%, then what is the percentage change in the volume?
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Answers

Answered by sourishsarkarkgec
1

Answer:

The percentage change in the volume is 29.6%.

Step-by-step explanation:

We know that volume of a cylinder is V=πr²h

Let r and h be the radius and height of a cylinder.

Given, Radius is increased by 20% and height decreased by 10%

radius=r+20/100r=6/5r

height=h-10/100=9/10h

∴ V =π(6/5r)²(9/10h)=(324/250)πr²h

Change in volume=(324/250)πr²h-πr²h

                              = 74/250 πr²h

∴Change in percentage=(74/250)πr²h/πr²h x 100

                                       =74/250 x 100

                                       = 29.6%

     ∴ Change in percentage=29.6%.

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