If the radius of a cylinder is increased by 20% and its height is decreased by 10%, then what is the percentage change in the volume?
NO SCAMS.
Answers
Answered by
1
Answer:
The percentage change in the volume is 29.6%.
Step-by-step explanation:
We know that volume of a cylinder is V=πr²h
Let r and h be the radius and height of a cylinder.
Given, Radius is increased by 20% and height decreased by 10%
radius=r+20/100r=6/5r
height=h-10/100=9/10h
∴ V =π(6/5r)²(9/10h)=(324/250)πr²h
Change in volume=(324/250)πr²h-πr²h
= 74/250 πr²h
∴Change in percentage=(74/250)πr²h/πr²h x 100
=74/250 x 100
= 29.6%
∴ Change in percentage=29.6%.
Similar questions