If the radius of a nucleus ²⁵⁶X is 8 fermi, then the radius of
⁴He nucleus will be
(a) 16 fermi (b) 2 fermi (c) 32 fermi (d) 4 fermi
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R=R0(A)1/3
∴ R2R1=(A2A1)1/3=(4256)1/3=4
R2=4R1=2 fermi
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