Physics, asked by gayatrisinghh06, 2 months ago

If the radius of a planet is twice the earth, the value of g will be __ times that of earth​

Answers

Answered by anusmitaghanty
1

Answer:

2.45 m/s

Explanation:

For instance, if an object were moved to a location that is two earth-radii from the center of the earth - that is, two times 6.38x106 m - then a significantly different value of g will be found. As shown below, at twice the distance from the center of the earth, the value of g becomes 2.45 m/s2.

Answered by Anonymous
1

Let, g be the g gravity of the Earth,

and g' be the gravity of the planet

g =  \frac{GM}{ {r}^{2} } \:  \:  \:  \:  \: .... (i) \\  \\ g' =  \frac{GM}{ {(2r)}^{2} }   \:  \:  \:  \:  \: ....(i)\\  \\  \frac{g}{g'}  =  \frac{ \frac{GM}{ {r}^{2} } }{ \frac{GM}{4 {r}^{2} } }  \\  \\  \\  \frac{g}{g'}  =  \frac{ \cancel{GM}}{  \cancel{{r}^{2} }}  \times  \frac{4  \cancel{{r}^{2}} }{ \cancel{GM} } \\  \\  \frac{g}{g'}  = 4 \\  \\ g' =  \frac{g}{4}

So, the gravity of planet will be 1/4 times the value of g of the earth.

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