Physics, asked by HarshitRanjanJha, 1 year ago

if the radius of a Planet shrinks by 2% while its mass remains the unchanged the acceleration due to gravity on the planet surface would increase or decrease?

Answers

Answered by 97650366da
41

planet surface would increase because


The acceleration due to gravity at the surface of earth is g = G m / R2  .

The radius of earth decreases by 2 %, therefore

R' = R - 0.02 R = 0.98R.

Now acceleration due to gravity will be :

g' = GM / ( 0.98 R )2  = 1.04 g

Percentage increase in acceleration due to gravity

[(g' - g )/g ] x 100 = 4 %

i hope this clarifies your doubt.

Regards


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priya7136: please tell me this answer
HarshitRanjanJha: the answer is increase
priya7136: the opposite angle of a paralleogram are given as (5×+3) and (4×+6) find the measure of all the angle
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97650366da: no
Answered by Anonymous
49
Hola User__________________

Here is Your Answer..!!!!
___________________________

⭐Actually welcome to the concept of the GRAVITATION...

⭐Now Basiclly we know that ......

⭐F = GMm/r^2 ...

⭐since we know that .. F = mg ( for a body at surface )

⭐thus we get that ....

⭐g = GM / r^2

⭐Now from this expression we can clearly see that the .... Acceleration due to gravity is always inversely proportional to the Radius of the planets ...

⭐so now we can say that. ..when the Radius decreases the Acceleration due to gravity (g) will increase as they are in inverse proportion to each other

⭐So the value of Acceleration due to the gravity increases

______________________________

Hope it helps u.....☺
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