if the radius of a Planet shrinks by 2% while its mass remains the unchanged the acceleration due to gravity on the planet surface would increase or decrease?
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Answered by
41
planet surface would increase because
The acceleration due to gravity at the surface of earth is g = G m / R2 .
The radius of earth decreases by 2 %, therefore
R' = R - 0.02 R = 0.98R.
Now acceleration due to gravity will be :
g' = GM / ( 0.98 R )2 = 1.04 g
Percentage increase in acceleration due to gravity
[(g' - g )/g ] x 100 = 4 %
i hope this clarifies your doubt.
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Answered by
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Hola User__________________
Here is Your Answer..!!!!
___________________________
⭐Actually welcome to the concept of the GRAVITATION...
⭐Now Basiclly we know that ......
⭐F = GMm/r^2 ...
⭐since we know that .. F = mg ( for a body at surface )
⭐thus we get that ....
⭐g = GM / r^2
⭐Now from this expression we can clearly see that the .... Acceleration due to gravity is always inversely proportional to the Radius of the planets ...
⭐so now we can say that. ..when the Radius decreases the Acceleration due to gravity (g) will increase as they are in inverse proportion to each other
⭐So the value of Acceleration due to the gravity increases
______________________________
Hope it helps u.....☺
Here is Your Answer..!!!!
___________________________
⭐Actually welcome to the concept of the GRAVITATION...
⭐Now Basiclly we know that ......
⭐F = GMm/r^2 ...
⭐since we know that .. F = mg ( for a body at surface )
⭐thus we get that ....
⭐g = GM / r^2
⭐Now from this expression we can clearly see that the .... Acceleration due to gravity is always inversely proportional to the Radius of the planets ...
⭐so now we can say that. ..when the Radius decreases the Acceleration due to gravity (g) will increase as they are in inverse proportion to each other
⭐So the value of Acceleration due to the gravity increases
______________________________
Hope it helps u.....☺
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