If the radius of a right circular cone is halved and height is doubled, then what is the volume of the new cone
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Volume of a cone is V = 1/3 pi r^2 h
Now when the height of the cone is doubled it becomes 2h, radius is halved, it becomes r/2
Putting these in the formula new volume will be 1/3 pi (r/2)^2 (2h)
= 1/3 pi {(r^2)/4} 2h
= 1/2 { 1/3 pi r^2 h}
= 1/2 the original volume
So, when the height of the cone is doubled and radius is halved, the new volume will become half the original volume.
rahulgrover033:
hlo
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Answer:
*The ratio of the volume of the reduced cone to that of the original cone is 1:4*
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