if the radius of a sphere is double what will happen to its surface area
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Answered by
6
Surface area of sphere=4πr²
Let the initial radius be R
SA=4πR²
Now when the radius is doubled:
new SA=4π(2R)² = 4× 4πR²
new SA= 4× 4πR²
= 4× (old SA) [because 4πR²=old SA ]
=4 × SA
So the new surface area will increase by 4 times.
Let the initial radius be R
SA=4πR²
Now when the radius is doubled:
new SA=4π(2R)² = 4× 4πR²
new SA= 4× 4πR²
= 4× (old SA) [because 4πR²=old SA ]
=4 × SA
So the new surface area will increase by 4 times.
Answered by
5
let the radius of the sphere be r
original surface area = 4 x pi x r^2
new radius = 2r
surface area
= 4 x pi (2r)^2
= 4 x pi x 4 r^2
now
surface area of original sphere/ surface area of new sphere
= (4 x pi x r^2) / (4 x pi x 4r^2)
=1/4
therefore
surface area of new sphere
= 4( surface area of original sphere)
original surface area = 4 x pi x r^2
new radius = 2r
surface area
= 4 x pi (2r)^2
= 4 x pi x 4 r^2
now
surface area of original sphere/ surface area of new sphere
= (4 x pi x r^2) / (4 x pi x 4r^2)
=1/4
therefore
surface area of new sphere
= 4( surface area of original sphere)
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