Question

if the radius of a sphere is doubled.then what is the increase in percentage of the surface of the sphere​

Answer 1

Answer:

he increase in percentage of the surface of the sphere​ is 300 %

Step-by-step explanation:

HI MATE.

Let the radius of a sphere be r.

Surface area of the sphere will be=

4πr^2

let the new doubled radius be R.

R=2r

Surface area of the new sphere will be=

4πR^2 = 4π(2r)^2 = 4π(4r^2) = 16πr^2

Area increased = Surface area of the sphere - Surface area of the new sphere 16πr^2 - 4πr^2 = 12πr^2

Percentage increase = (Area increased / Surface area of the sphere) x 100

= (12πr^2 / 4πr^2) x 100 = 3 x 100 = 300 %