If the radius of a sphere is doubled then what is the ratio of their volumes
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Hello mate!!
Let the radius of smaller sphere be r,
Then, the radius of the bigger sphere =2r
Now,
Volume of the smaller sphere=4/3pi*r^3
Then,
The Volume of the bigger sphere =4/3pi*r^3=4/3pi*(2r) ^3=4/3pi*8r^3
Now,
The ratio of there volumes=Volume of the smaller sphere/Volume of the bigger sphere
=>4/3pi*r^3/4/3pi*8r^3
=>1: 8 [ 4/3, pi and r^3 cancel each other when dividing]
So, The answer is 1: 8
Thanks for Questioning...
Please mark my answer as brainliest..
Let the radius of smaller sphere be r,
Then, the radius of the bigger sphere =2r
Now,
Volume of the smaller sphere=4/3pi*r^3
Then,
The Volume of the bigger sphere =4/3pi*r^3=4/3pi*(2r) ^3=4/3pi*8r^3
Now,
The ratio of there volumes=Volume of the smaller sphere/Volume of the bigger sphere
=>4/3pi*r^3/4/3pi*8r^3
=>1: 8 [ 4/3, pi and r^3 cancel each other when dividing]
So, The answer is 1: 8
Thanks for Questioning...
Please mark my answer as brainliest..
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