If the radius of a sphere is doubled, which is the ratio,of the volume of the first sphere to that of the secon sphere?
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Answer:
ratio=1:8
Step-by-step explanation:
let original radius be r
so the original volume=4/3π(8r^3)
New radius = 2r
so, New radius=4/3π(2r)^3=4/3(8π)^3
Ratio=4/3π^3divided by 4/3π(8r)^3 then cancelled =1/8 in ratio=1:8
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