if the radius of a sphere is halved then the decrease in its surface area is
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Answer:
(i) decrease in surface area is 4πr² - 1πr² = 3πr²
(ii) decrease in surface area is 75%
Step-by-step explanation:
let the radius of the sphere be = r
then surface area will be 4πr² ............. (i)
now if the radius is halved then let the radius be = r/2
then the surface area will be 4π(r/2)² = 4πr²/4 = 1πr².........(ii)
decrease in surface area is 4πr² - 1πr² = 3πr²
percentage of decrease in area in area will be 3πr²/4πr² × 100
=> 3 / 4 × 100
=> 3 × 25 = 75%
decrease in surface area is 75%
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