If the radius of a sphere is halved ,what will be the change in its surface area ?
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We know SA of a sphere is S1 =4πR2 .
When the radius is halved ,the new SA is S2=4π(R/2)2 = 4πR2 /4 =S1 /4
The new SA S2 is 1/4th of the original SA S1
When the radius is halved ,the new SA is S2=4π(R/2)2 = 4πR2 /4 =S1 /4
The new SA S2 is 1/4th of the original SA S1
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Given :
the radius of a sphere is halved
To Find :
what will be the change in its surface area ?
Solution:
Let the radius of sphere be r
Surface area of sphere =
Radius of sphere is halved
So, New radius =
Surface area of new sphere =
So, Surface area of new sphere =
So, Surface area of new sphere is one fourth of surface area of original sphere
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