if the radius of a sphere is increased by 100/7% then the surface area of the sphere is increased by how much percentage
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Answer:
1500/49% or 30.61%
Step-by-step explanation:
Surface Area of sphere = 4πr^2
If r = 1, S.A. = 4π
New r = 1 + 100/7% = 1 + 1/7 = 8/7
New S.A. = 4π(8/7)^2 = 4π × (64/49)
Percentage increase = (New S.A. - S.A) / S.A. × 100
= [4π(64/49 - 1)]/4π x 100
= 15/49 × 100
= 1500/49% or 30.61%
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