Question

If the radius of a sphere is increased by 50%,find the percentage increase in surface area .​

Answer 1

Answer:

237.5%. Hence increase volume in percent is 237.5%.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the original radius be r.So, the surface area of the sphere =4πr 2 .......(1)Since, the radius is increased by 50%, thenThe new radius =1.5rTherefore, the new surface area of the sphere will be=4π(1.5r) ^2 =2.25×4πr^2 .........(2)Therefore, the required percentage= 2.25×4πr^2−4πr^2/4πr^2×100 =1.25×1.25×4πr^2h/4πr^2h×100=125%Hence, this is the answer.