Math, asked by bipro36, 4 months ago

if the radius of a sphere is tripled then what is the ratio of the volume of original sphere to that of the second.​

Answers

Answered by abinash619
0

Answer:

1:9

Step-by-step explanation:

for 1st sphere

v1=1/3*πr³

for 2nd sphere

v2=1/3*π(3r³)

v1:v2=1/3*πr³:1/3*π(3r)³

=r³:(3r)³

=1:9

Answered by brokendreams
1

Ratio of Volume of original sphere to the second sphere is 1 : 27.

Step-by-step explanation:

Step 1 - Volume of First or original sphere

Radius of sphere = r

Volume of sphere = V = \frac{4}{3} × π × r^{3}

Step 2 - Volume of second sphere

Radius of second sphere = 3r

Volume of second sphere = V' = \frac{4}{3} × π × (3r)^{3}

                                          =   \frac{4}{3} × π × 27 r^{3}

Step 3 - Ratio of Volume of first sphere to the second sphere

    \frac{V}{V'}  =  \frac{ \frac{4*\pi*r^{3} }{3} }{ \frac{4 * \pi*27 * r^{3} }{3} }   =  \frac{1}{27}

and the ratio of V : V' = 1 : 27.

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