if the radius of an atom of an element is 75pm and the lattice type is BCC.what is the edge of unit cell
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Answer:
For body centered cubic lattice, the relationship between the edge length a and the radius r is as given below:
a=
3
4r
Substituting values in the above expression, we get
a=
3
4×75
=173.2 pm
Hence, the edge length of the unit cell is 173.2 pm.
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