If the radius of base and height of a cone are increased by 10%, find the percentage of increase of its volume
A) 33.5%
B) 33.1%
C) 32.1%
D) 53.1%
Answers
Answered by
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If the radius of base and height of a cone are increased by 10%, find the percentage of increase of its volume
A) 33.5%
B) 33.1%
C) 32.1%
D) 53.1%
Answer: B) 33.1%
SOLUTION
v1= 13πr12h1
v2=13πr22h2
% Increase in volume = (V2-V1) / (V2*100)
.
.
THANKS ☺️
A) 33.5%
B) 33.1%
C) 32.1%
D) 53.1%
Answer: B) 33.1%
SOLUTION
v1= 13πr12h1
v2=13πr22h2
% Increase in volume = (V2-V1) / (V2*100)
.
.
THANKS ☺️
Answered by
2
⭐⭐ heya mate ⭐⭐
here is the answer
➖➖➖➖➖➖➖➖➖➖➖➖➖⬇
Volume of cone = πr²h/3
New radius = 11r/10
new height = 11h/10
So new V = π(11r/10)²)(11h/10)(1/3)
=π(121r/100)(11h/10)(1/3)
= π 1331rh/3000
Percentage increase = (New volume/Oldvolume * 100) -100
= (π/3 * 3/π *1331/1000 * rh/rh * 100) -100
= (1331/1000 * 100) -100
= 133.1 -100
= 33.1%
here is the answer
➖➖➖➖➖➖➖➖➖➖➖➖➖⬇
Volume of cone = πr²h/3
New radius = 11r/10
new height = 11h/10
So new V = π(11r/10)²)(11h/10)(1/3)
=π(121r/100)(11h/10)(1/3)
= π 1331rh/3000
Percentage increase = (New volume/Oldvolume * 100) -100
= (π/3 * 3/π *1331/1000 * rh/rh * 100) -100
= (1331/1000 * 100) -100
= 133.1 -100
= 33.1%
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