if the radius of base of a circular cylinder is halved keeping the height same then find ratio of volume of reduced cylinder to that of original cylinder
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volume of cylinder = 1/3 * pi * r^2 * h
if radius is halved, volume will become 1/4 of the original volume
if radius is halved, volume will become 1/4 of the original volume
anushka289:
can you solve it full properly
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volume=22/7×r^2×h
if radius of base is halved, then
volume=22/7×r×h
RATIO of reduced cylinder volume to volume of original cylinder
22/7×r^2×h : 22/7×r×h
r^2 : r
r×r : r
2 : 1
if radius of base is halved, then
volume=22/7×r×h
RATIO of reduced cylinder volume to volume of original cylinder
22/7×r^2×h : 22/7×r×h
r^2 : r
r×r : r
2 : 1
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