If the radius of cylinder is halved and height is doubled then what will be the curved surface area?
(a) Increase by 1 (b) the same (c) double
(b) the same
(c) double
(d) triple
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let initial radius be x
final be x/2
let initial height be h
final be 2×h
initial curved surface area of cylinder. = 2πrh.......(1)
final curved surface area =
=2πrh.........(2)
from 1 and 2 since both r same
so option b is correct
hope this will help you
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