Question

If the radius of each
circle in the image is
6 cm, what is the
area (in cm?) of the
quadrilateral formed
by joining the
centres
of
the
circles?​

Answer 1

Answer:

12 multiply by 12

= 144cm^2 ok bro

Answer 2

Given :  radius of each circle in the image is 6 cm,

To Find : what is the  area  of the quadrilateral formed by joining the centers of the circles

36√3

64√3

72√3

84√3​

Solution:

Quadrilateral ABCD is a rhombus with each side = 6 + 6 = 12 cm

one Diagonal AC = 6 + 6 = 12 cm

Quadrilateral ABCD can be split into  two Equilateral triangles

ΔABC  & ΔADC

Each of Side Equal to 12 cm

Area of Equilateral Triangle with side 12 cm  = (√3/4)12²

= 36√3  cm²

Area of  ΔABC =  36√3  cm²

Area of  ΔADC =  36√3  cm²

Area of  Quadrilateral ABCD = Area of  ΔABC + Area of  ΔADC

=  36√3 +    36√3

= 72√3   cm²

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