if the radius of each circle in the image is 6 cm what is the area in centimetre square of the quadrilateral formed by joining the centres of the circle
Answers
Answer:
2
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Step-by-step explanation:
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Answer:
The area of the quadrilateral formed is 72√3 cm².
Step-by-step explanation:
Given:
Radius of each circle (r) = 6cm
To find:
Area of the quadrilateral (A)
Solution:
Quadrilateral ABCD is a rhombus having sides 6 + 6 = 12cm
One diagonal AC = 6 + 6 = 12 cm
Quadrilateral ABCD can be split into two equilateral triangles ΔABC and ΔADC having sides 12cm.
The area of an equilateral triangle is given as (√3/4)side². Therefore, the area of an equilateral triangle with side 12 cm = (√3/4)12² = 36√3 cm²
Area of ΔABC = 36√3 cm²
Area of ΔADC = 36√3 cm²
Therefore, area of quadrilateral ABCD is given as
A = Area of ΔABC + Area of ΔADC
A = 36√3 + 36√3
A = 72√3 cm²
Hence, the area of the quadrilateral formed by joining the centers of the circles is 72√3 cm².
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