Question

If the radius of earth is 0.2 percentage without change in its mass the percentage change in its angular velocity

Answer 1

Answer:

R

′

=R(1−0.002)

Using conservation of angular momentum

5

2

MR

2

ω

i

=

5

2

MR

2

(1−0.002)

2

ω

f

ω

i

=ω

f

(1−0.002)

2

ω

f

=ω

i

(1−0.002)

−2

ω

f

=ω

i

(1+0.004)

i.e. w

f

is increased by 0.4%

We used (1+a)

−n

=1−an

if a≪1