If the Radius of Earth is decreased by 1 % , it's mass remaining same . The acceleration due to gravity on the surface of eartj will ?
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Heya....!!
Let R'' be the new radius of Earth then ,
R"" = R - 1/100R = 99/100R
» (0.99)R
g' = GM/R""^2
= GM/0.99^2R^2 >> 1.02 g
%increase in the value of g = g'-g÷g×100
=» 1.02g-g/g ×100 = 0.02×100
% increase in the value of g = 2% .
HOPE IT HELPS U
Let R'' be the new radius of Earth then ,
R"" = R - 1/100R = 99/100R
» (0.99)R
g' = GM/R""^2
= GM/0.99^2R^2 >> 1.02 g
%increase in the value of g = g'-g÷g×100
=» 1.02g-g/g ×100 = 0.02×100
% increase in the value of g = 2% .
HOPE IT HELPS U
Ddbb:
thanks
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