If the radius of Earth is doubled, keeping the mass constant, the acceleration due to gravity on the surface will now be
a) 39.2m/s²
b) 20m/s²
c) 2.4m/s²
d) same as before
please answer correctly..
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Acceleration due to gravity = g
Therefore ,
g = GM / (R)^2
= GM / (2R)^2
= GM / 4 R^2
= (GM / R^2 ) 4
= 10 / 4 [ ( GM / R^2 ) = 10 m/s^2 ]
= 2.4 m/s^2
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Therefore ,
g = GM / (R)^2
= GM / (2R)^2
= GM / 4 R^2
= (GM / R^2 ) 4
= 10 / 4 [ ( GM / R^2 ) = 10 m/s^2 ]
= 2.4 m/s^2
[ Please mark this answer as brainliest answer]
____Welcome____
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