if the radius of Earth's orbit is made 1/4 the duration of an year will become
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To solve this problem we can resort to Kepler’s third law of orbital motion and it states that the square of the average orbital period of a planet is proportional to the cube of its average orbital radius such that;
T2∝R3T2∝R3
So here is the math :
Look at the pic now :
the orbital period of the Earth, i.e. a year would decrease to 365/8≈45.6365/8≈45.6 days
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