if the radius of earth shrink by two percent mass remaining constant then how would the value of acceleration due to gravity change
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the value of g is increases if the radius of the earth is shrik by 2 percent and mass remain constant .
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acceleration due to gravity (g) depends on mass (m) and radius (r) of the earth as
![g = \frac{gm}{{r}^{2} } g = \frac{gm}{{r}^{2} }](https://tex.z-dn.net/?f=g+%3D++%5Cfrac%7Bgm%7D%7B%7Br%7D%5E%7B2%7D+%7D+)
if mass is constant then "g" is inversely proportional to the square of Radius of the earth.
![\frac{g2}{g1} = \frac{ {(r1)}^{2} }{(r2) {}^{2} } = \ { (\frac{100}{98} )}^{2} \frac{g2}{g1} = \frac{ {(r1)}^{2} }{(r2) {}^{2} } = \ { (\frac{100}{98} )}^{2}](https://tex.z-dn.net/?f=+%5Cfrac%7Bg2%7D%7Bg1%7D++%3D+++%5Cfrac%7B+%7B%28r1%29%7D%5E%7B2%7D+%7D%7B%28r2%29+%7B%7D%5E%7B2%7D+%7D++%3D++%5C+%7B+%28%5Cfrac%7B100%7D%7B98%7D+%29%7D%5E%7B2%7D++)
so,
![g2 = {( \frac{100}{98} )}^{2} \times g g2 = {( \frac{100}{98} )}^{2} \times g](https://tex.z-dn.net/?f=g2+%3D++%7B%28+%5Cfrac%7B100%7D%7B98%7D+%29%7D%5E%7B2%7D++%5Ctimes+g)
if mass is constant then "g" is inversely proportional to the square of Radius of the earth.
so,
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