Chemistry, asked by kemingenious, 10 months ago

If the radius of first Bohr's orbit of H-atom is x, which of the following is the INCORRECT conclusion
(A) The de-Broglie wavelength of electron in the third Bohr orbit of H-atom = 6 π X.
(B) The fourth Bohr's radius of Het ion = 8x.
(C) The de-Broglie wavelength of electron in third Bohr's orbit of Li2+ = 2πx.
(D) The second Bohr's radius of Be2+ = x

Answers

Answered by chasetomek2023
3

Answer:

26 i think

Explanation:

Answered by krishna210398
0

Answer:

Correct option is B)

Explanation:

According to Bohr's postulate,

mvnrn=nh/2π (nthorbit)

radius of nth orbit, rn=n2.r1

given that r1=x

thus in third orbit: m.v3.r3=3h/2π

Debroglie wavelength in 3rd orbit is given by:

λ=h/m3v3

thus λ=2π.r3/3

or λ=2π.32x/3

λ=6πx

Thus If the radius of the first Bohr orbit of H atom is x, then de Broglie wavelength of an electron in 3rd orbit is nearly 6πx

So, option B is correct.

#SPJ2

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