If the radius of first Bohr's orbit of H-atom is x, which of the following is the INCORRECT conclusion
(A) The de-Broglie wavelength of electron in the third Bohr orbit of H-atom = 6 π X.
(B) The fourth Bohr's radius of Het ion = 8x.
(C) The de-Broglie wavelength of electron in third Bohr's orbit of Li2+ = 2πx.
(D) The second Bohr's radius of Be2+ = x
Answers
Answered by
3
Answer:
26 i think
Explanation:
Answered by
0
Answer:
Correct option is B)
Explanation:
According to Bohr's postulate,
mvnrn=nh/2π (nthorbit)
radius of nth orbit, rn=n2.r1
given that r1=x
thus in third orbit: m.v3.r3=3h/2π
Debroglie wavelength in 3rd orbit is given by:
λ=h/m3v3
thus λ=2π.r3/3
or λ=2π.32x/3
λ=6πx
Thus If the radius of the first Bohr orbit of H atom is x, then de Broglie wavelength of an electron in 3rd orbit is nearly 6πx
So, option B is correct.
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