If the radius of first Bohr's orbit of hydrogen atom is 'x' then de Broglie wavelength of electron in
3rd orbit is nearly
(A) 2πx
(B) 6πx
(C) 9x
(D) x/3
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Broglie wavelength of the electron in the 3rd orbit would nearly be the 6πx.
Explanation:
Given,
= x
As per Bohr's postulate,
= nh/2π (nth orbit)
As we know that,
Radius in nth orbit equals to
A.T.Q.
In 3rd orbit = m. = 3h/2π
To find Broglie wavelength of electron, we will use;
λ = h/
so,
λ = (2π.)/3
λ = [2π x]/3
∵ λ = 6πx
Thus, the Broglie wavelength of the electron in 3rd orbit would be likely 6πx.
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